Try pausing 🤪

The pause button is your friend. 👍

Watch it in slow speed or take a screen shot

Yeah it’s “inconveniently” quick. Even “precise seeking” (on iPad, anyway) misses it.

Kkkkk

Never mind the red/green, what about that 2.2k resistor to keep the LEDs from seeing 14V that’s not in the schematic. Tell you what, if these guys are this sloppy I don’t think I’ll be hooking anything up to line voltage ;-)

that is a dangerous circuit this guy is an idiot to propose it as a beginner project

Yeah, the way it’s drawn it’s a voltage divider from - to - lol. Nice use of bridge, haven’t seen it used as a series device before

Second schematic also wrong!😉

@@mr_tom_1_0 It was once a common way to use thyristors to switch both sides of an AC cycle before triacs became commonly available. This circuit could be built with a triac instead and then it wouldn't need the bridge as the rest of the components are non polarised.

@@Fedor___1 si esta mal el transistor no se puede conectar a la entrada sino al la salida para que testee la tension de salida cuando es la tension alta se corta

4s QE da Streetnnnnnññnnnnnn jj😢😢😢😅​@@mr_tom_1_0

Please watch video without skipping, i have already shown circuit diagram of each project 😄

I agree. Also there the LEDs have no current limit resistors shown in the schematic so they will burn out instantly.

My two cents. For the circuit to work, J15 should be connected to a current controlled voltage source. When the battery voltage is low, the current will be maximal and the voltage on J15 will also low. Low enough the keep the transistor driven via the base connected to the potentiometer in its of position and the relais in the off state. The battery will be charged via contact pin 3. When the battery voltage rises, the voltage on J15 will also increase. At a certain moment the voltage on the base of the transistor will be high enough to activate the relais. The voltage on J15 will now switch via pin 4 to the other led. This will lower the current far under the maximum value, so the current controlled voltage source will now run in voltage controlled mode and drive J15 with its preset voltage. And yes both LEDs do need a series resistor for protection. When the current controlled voltage source on J15 is disconnected and reconnected again, the relais is activated directly again as there is no load current needed. In the current diagram, the relais is drawn in its activated state. So yes, the words chrg and full need to be swapped. The 1N5408 diode is to prevent discharging of the battery via the led when the relais is activated.

What is the purpose of this gadget There is no explanation

why say that

why

Pause the video, then!

Because they're wrong!😉