it is rather german accent

nope

maketheworldgreatagain diewzlt no. I'm dutch and recognize this anywherr

karakter

Yes a dutch accent

you would need to have the arduino read the potentiometer position and then to display that value on the display

The LED

Yellow

@@logmaker3609 give us the fucking sketch...

@@shobalengheru see code link :)

same here....

sort of

@@logmaker3609 means yes. How to avoid?

@@snk9970 It can't be helped because 1 has only two segments and 7 has 3 compared to the others which have 4 or more segments to light up. My solution is to attach resistors to each of the segments from segA to segG so each segment of the 7-segment displays receives equal current. Indeed, in my implementation of this where I used 220R for each of the 7 segments, I have all numbers 0-9 all equally bright.

Delay(1000);

@@logmaker3609 with that way ,I can 't see the numbers.

Delay (9999999999999999999)

It is a function, the last one in the sketch. Remember in C you can write functions on the Bottom.

@@logmaker3609 My Arduino is telling me that I can't. Where do you first declare it as a function?

@@tylerbyrne8019 ukposts.info/have/v-deo/sJSWp42Ib2uWlp8.html

Yes same question, as if he would control it through that coin

for scale hiw big the display is

I think that the four separate display pins are the current return path return for each of the four seven set displays, therefore these four are effectively the (4) GND pins.

@@malcolmwright7440 what if we set +5V in all the pins at the same time?

@@henriqueers LED displays are just LED's arranged in a specific pattern with either the anodes or the cathodes of the 8 segments ( a,b,c,d,e,f,g and decimal point) combined at one point. As you Power each 8 segmented part, e.g you supply the current source to the combined point, you then activate any or the 8 segments by supplying a return current path to the segment path return, (GND ?!) which are also connected to the same related segment (commoned) with the other 8 segmented displays, e.g all a's connected together, all b's connect with each other ect etc.... In answering your question, if you supply the same potential to both these "feed" and "return" pins then NO current will flow and the LED's will not be powered. You need a differential potential across the LED's to provide a forward current flow to energize illumination, so with a "common anode" display, the common 8 segments pin is connected to positive and the return of the LED pins are wired to a current limiting negative return. Hope this is clear 😅