Cow skin its a very good conductive material, it smells bad after one day but otherwise very good, even better than carbon nanotubes.

I'm not very fluent in C++, where did you find this? I guess it's incrementing by 1 every cycle? cheers!

@@33Initiative Hi there. I was referring to the How it works section on this document. playground.arduino.cc/Main/CapacitiveSensor/

Mike come on!!! whe all know about that!! stop listening to Dude Perfect :D

Yes it would be sensitive to how much pressure you apply to the contact plate. The reason, however, reveals two inaccuracies in the description, which are worth discussing. The first inaccuracy is the claim that the change in time is all about changing capacitance. In reality, the connection with the body when you're touching the plate adds a complex circuit consisting primarily of a variable resistance in series with a capacitance. When you touch the contact plate lightly, you connect the capacitance of the body through a very high resistance. As you apply more pressure, you reduce the contact resistance between the contact plate and your body. The lower the resistance, the higher the charging current drawn by the capacitor. Now you would think that the higher total resistance would increase the time constant and therefore increase the time for the input pin to rise to the voltage of the output pin, but that's not what happens, which is the second inaccuracy. While the total time constant does actually increase with higher contact resistance, that is not what is important in this case. Remember that we have the fixed resistance in the circuit AND the variable resistance of the contact of the body to the plate. The input pin is connected to the junction of these two resistances. When the contact resistance is high - with a light touch - the maximum possible charging current into the capacitance is reduced. This means that the voltage drop across the fixed resistance caused by the lower charging current is lower, so the input pin rises to match the voltage at the output pin much faster than with a lower contact resistance. It turns out - and I suppose this is technically a third inaccuracy, if only by implication rather than by direct statement - that the capacitive touch effect is more about changing resistance than changing capacitance when you're actually touching the plate. As you approach the plate - before you touch it - you add another small but variable capacitance in series with an extremely high contact resistance, complicating the circuit still further, and and resulting in two different modes of operation, but that's another story!

I mean the resistor + Capacitor why do I need to delay the time?

@@TheRno0o The delay is a way of us detecting how much capacitance there is. If there is higher capacitance, there will be a longer delay. Because the capacitor is always the same, it will be the same each time. When your finger comes close, it starts to act as a capacitor. Because there is more capacitance, it makes the delay longer. So now if we switch the wire from low to high, or high to low, it will take longer than normal for the pin to go whatever the other pin went. This little delay is taken advantage of, and for you to understand this you kind of need to understand how a microchip works. Basically it will send the pin high, and it will detect the delay. When you put your finger on the capacitor, and you switch the pin to High, it will take longer for the other pin to go high, because there is more capacitance, because your finger has capacitance. So when you move your finger up, there is more capacitance, and it takes longer, and this extra delay is detected by the microchip, and it assumes that the extra delay is the fact that we touched it. Hopefully that makes sense

Yeah, but he's shorting stuff for people who are new to this to understand better.

The body itself is not a capacitor. A capacitor has 2 plates or 2 bodies with a diaelectric between them.

The material itself acts as a capacitor, and your body ALSO acts as a capacitor, connected in parallel, both capacitances would sum up to a greater total capacitance, as explained in the video

Yes, I think Luciano has it right. @@lucianosaldivia5917