In don't think I have the level for that...

@@ELECTRONOOBS it would be great and pragmatic book for hobbyists, I'd buy it for sure!

@@ELECTRONOOBS in your explanation ,with the circuit of Bootstrap the 24 volt is made with the load voltage 12 + the bootstrap capacitor 12 ,it is not 24 before turning on the MOSFET. Anyway nice video I able to learn something new here

Those of us who are his fans would buy it most likely. But people don't enjoy reading textbooks for the most part. Why would he focus his efforts on a textbook that would reach a very small audience when he can focus his attention on these shorter and easier to digest videos that reach a far wider audience? He makes more impact on his channel. If you're looking for textbooks go check out Jim Pytel's channel

​@@ELECTRONOOBS bro I want to study radio transmission from basic how it works and how to build one do you have any recommendations Love your content bro❤❤❤😊😊

Thank upu!

do you mean the best n-channel, or the best p-channel? :P

Make some interesting projects man

What is the signal frequency the Pokit Meter supports? Can it do real time plotting of the signal as well. I want to buy a couple but would like these two questions answered. I have a friend in Pakistan I want to send one to. *The other one is for me*

Do you have an ardruino course in English?

I use bootstrap in html😅🤣

Glad to hear that!

the capacitor is charged extremely fast over the diode, when the mos is off, as there is no resistance involved; in the beginning after powering it on, as the mos is off, the capacitor is charging (fast), until you turn it on first time; when the mos is on, the capacitor discharges very slow through the gate of the mos (nano/pico amps?) and through the reversal current of the diode (also nano/pico amps, so at most a micro amp is lost, or so); so, you NEED the "off" time, to charge the capacitor, you can not let it continuously in "on" state, because after a while, the capacitor will discharge enough to turn the mos to a "partially" off state, where it just dissipate the energy and possible kill your load (if supplying it with intermediary voltage can kill it); so, this is designed to work in a "pwm" environment, you can make the mos "off" continuously, static, but you need to make it "on" with pwm (say, between 85% and 99%, depending on your/load/needs); with this in mind, the "DIY" circuit is as fast as the integrated drivers, or even faster: with carefully tuned components you can get 30-500 ns switch time (the drivers have ~150, but also about 500ns dead time); mind that the drivers also need external capacitor and diode, however, the advantage of the drivers is the very low EMI (the "DIY" circuit will generate a lot of EMI in on state), the fact that you can command 2 channels and you can easily switch off both of the channels in the same time, and the safety of having a dead time in between, to ensure that both moses are not switched on in the same time (which can cause a short circuit and some fireworks in the room).

@@laurv8370 Thanks for the very detailed explanation! I understood the part about the circuit being designed for PWM applications, I was just wondering about how quickly the capacitance of the transistor’s gate could be charged (and therefore how quickly the voltage on the gate would rise), given that there was a resistor between the capacitor and the gate. 30-500ns answers that question. I expected it to be slower than a driver IC because the IC would have active circuitry to drive the gate, which would have much lower impedance. As you point out though, there will be a propagation delay through the IC, you still need the capacitor and resistor and the driver may have less of (or no) advantage for lower-power FETs, which would have lower gate capacitances. Thanks again for taking the time to give such a thorough answer!

Logic level n-channel as a low side switch, he touches on that. Watch a second time :) Then there's the issue of switching losses at high pwm frequencies due to the current limitations of gpios, that he didn't touch (to keep the video simple and quick, I suppose)

@@dbuezas Thanks will do! I must have missed that!

That puzzled me too, seems like almost nobody mentions it. When the mosfet opens, the potential at the source changes and is now 12V, and this adds to the already charged 12V of the capacitor, which now is electrically in series with the potential at the source, with the diode suddenly blocking. The 10K is not a pull-up resistor in the typical sense (from Vcc), but we can call it a bootstrap pull-up resistor as it provides higher gate voltage by the "higher rail", i.e. from the cap charged to Vcc in series with Vcc at the source as the mosfet opens.

Please make video on multivibrator E.g.. astable multivibrator

Lol.

When you accidentally capitalise the M: It was supposed to be 8mΩ

1M sample/sec. see full specs here: www.pokitinnovations.com/specifications/

@@rowanbell4361 thats low for my application, i need min 20 Ms/s

When I Will have time...

@@ELECTRONOOBS Plz try in next video it is very important to me

Enhancement MOSFETs are normally off while depletion MOSFETs are normally on. Depletion MOSFETs are very rarely used and enhancement MOSFETs are used about 100% of the time.

The 1n4148 is a switching diode. It is fast, but low currents. It will work fine for bootstrapping

I agreed with you. It seems to me the explanation is not right.

The explanation is correct indeed.

How did you come to this conclusion? When the MOSFET is On the initial +12V on the capacitor is blocked by diode and thus cannot add an additional +12V to the load

Not yet. But for sure someone will still their design.